Question

if a+b+c=0 and a^2+b^2+c^2=16, find the value of ab+bc+ac

Answer 1

Hi there!

Given :-

→ a + b + c = 0
→ a² + b² + c² = 16

We know that :-
(a + b + c)² = a² + b² + c² + 2(ab + bc + ac)

On substituting th' terms,

0² = 16 + 2(ab + bc + ac)

2(ab + bc + ac) = -16

ab + bc + ac = -16 / 2

ab + bc + ac = -8

Hence, The required answer is :-
ab + bc + ac = -8

Hope it helps! :)

Answer 2

Heyyy mate!!!!
Here is ur answer

Hope this helps u Please make me as a brainliest