Question

if a+b+c=0 and a^2 +b^2 +c^2 =16 find the value of ab +bc +ca

Answer 1

Answer:

(a+b+c)²=a²+b²+c²+2(ab+bc+ca)

0²=16+2(ab+bc+ca)

-16/2=(ab+bc+ca)

-8=ab+bc+ca

Hope it helps u.....^_^