Question

if a+b+c=0 and a^2+b^2+c^2=26. find the value of ab+bc+ca?​

Answer 1

Answer:

it can be done using an identity

Step-by-step explanation:

(a+b+c)²=a²+b²+c²+2(ab+bc+ca)

putting the values

(0)²=(a²+b²+c²)+2(ab+bc+ca)

0=(26)+2(ab+bc+ca)

-26=2(ab+bc+ca)

(ab+bc+ca)=-13

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Answer 2

Answer:

-13

Step-by-step explanation:

Hope it helps you

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