Question

If a + b + c = 0 and a^2 + b^2 + c^2 = k ( a^2 - bc) then find the value of k ?

Answer 1

★ Solution :-

Given ,

• a + b + c = 0
• a² + b² + c² = k (a² - bc)

We need to find ,

• k = ?

a + b + c = 0

a = - ( b + c ) = - b - c

Assuming as equation 1

( a + b + c ) = 0

Squaring on both sides

→ ( a + b + c )² = 0²

→ a² + b² + c² + 2(ab + bc + ac) = 0

→ k(a² - bc) + 2(ab + bc + ac) = 0

[ °.° Given ]

→ k ( a.a - bc ) + 2(ab + bc + ac) = 0

→ k [ a( - b - c ) - bc ] + 2(ab + bc + ac) = 0

[ °.° Equation 1 ]

→ 2(ab + bc + ac) = - k [ a( - b - c ) - bc ]

→ 2(ab + bc + ac) = - { - [ k ( ab + ac + bc) ]

→ 2(ab + bc + ac = k (ab + ac + bc)

→ K = 2

[°.° By comparing ]

Answer 2

Answer:

you only told answers no bro