Question

if a + b + c = 0 and (a+b-c)x^ 2 +(b+c-a ) x + (c + a - b) = 0 has real and equal roots, then the root is​

Answer 1

Answer:

If the roots of the equation (b-c)x2+(c-a)x +a-b=0 are equal,then prove that 2b=a+c. If the roots of the equation (b-c)x2+(c-a)x +a-b=0 are equal,then prove that 2b=a+c.

Answer 2

Step-by-step explanation:

2b=+ac this is yout answer