if a + b + c = 0 and a square + b square + c square = 1 then find the value of a raise to the 4 + b raise to the 4 + c race to the 4
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As we know,
(a+b+c)=a^2+b^2+c^2+ab+bc+ca
Using a+b+c=0
And a^2+b^2+c^2=1
=>(1)^2=a^4+b^4+c^4+2(0)
=>1=a^4+b^4+c^4+0
=>1-0=a^4+b^4+c^4
=>1=a^4+b^4+c^4
Hence,the value of a^4+b^4+c^4 is 1.
(a+b+c)=a^2+b^2+c^2+ab+bc+ca
Using a+b+c=0
And a^2+b^2+c^2=1
=>(1)^2=a^4+b^4+c^4+2(0)
=>1=a^4+b^4+c^4+0
=>1-0=a^4+b^4+c^4
=>1=a^4+b^4+c^4
Hence,the value of a^4+b^4+c^4 is 1.
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