If a+b+c=0, and a2+b2+c2=16, find the value of ab+bc+ca
Answers
Answered by
1
Answer:
Step-by-step explanation:
Just find 0
The value is 0
Answered by
3
Answer:
correct answer is -8
Step-by-step explanation:
identity is
(a+b+c) whole square =a square +b square +c square +2ab +2bc+2ca
putting given values in identity
0=16+2(ab+bc+ca)
2(ab+bc+ca)=-16
(ab+bc+ca)=-8
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