Question

if a+b+c =0 and a2 +b2 +c2 =16, finf ab+bc+ca​

Answer 1

Answer:

(a+b+c)² = a²+b²+ c²+2ab+2bc + 2ca

(0)² = 16 + 2(ab+bc+ca)

0 = 16+2(ab+bc+ca)

-16 = 2(ab+bc+ca)

-16/2 => ab+ bc + ca

-8 = ab +bc +ca

Answer 2

Step-by-step explanation:

$(a + b + c) {}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2ab + 2bc + 2ca$

$(0) {}^{2} = 16 + 2(ab + bc + ca)$

$- 16 = 2(ab + bc + ca)$

$\frac{ - 16}{2} = ab + bc + ca$

$ab + bc + ca = - 8$

$answer...$

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