Question

if a+b+c=0 and a2+b2+c2=26 find the value of ab+bc+ac​

Answer 1

Answer:

a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)

substituting the values

(0)(26-(ab+bc+ca))=0

when we multiply anything by zero it's value is going to be zero so the value of ab+bc+ca=0