If a + b + c = 0 and a2 + b2 + c2 = k (a? - bc) then k =?
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a+b+c=0
Squaring,
a²+b²+c²+2(ab+bc+ca)=0
So, a²+b²+c²=k=-2ab-2bc-2ca
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Here is the solution. Please mark it as the brainliest answer. :)
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