if a+b+c=0 and ab+bc+ca=26, find 2 (a+b+c).
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Answered by
1
Given
a+b+c=0and ab+bc+ca=26
Then,2(a+b+c)=2(0)
=0
a+b+c=0and ab+bc+ca=26
Then,2(a+b+c)=2(0)
=0
Answered by
1
2a+2b+2c=26
=2(a+b+c)=26
as 2 became common
=2(a+b+c)=26
as 2 became common
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