Question

if a+b+c=0 dind value of a²/bc+b²/ca+c²/ab​

Answer 1

Answer:

3

Step-by-step explanation:

a^2/bc + b^2/ca + c^2 / ab

= (a^3 + b^3 + c^3) / abc

= (a^3 + b^3 + c^3 -3abc + 3abc) / abc   . . . (1)

We know the formula,

a^3 + b^3 + c^3 -3abc = (a+b+c)*(a^2+b^2+c^2-ab-bc-ca)

Since a+b+c=0,

So, a^3 + b^3 + c^3 -3abc = 0

So, from (1), we have our answer,

3abc/abc = 3

Answer 2

$\sf{SOLUTION :-}$

☆ By Using the formula:-

» a³+b³+ c³

= ( a + b + c ) ( a² + b² + c² ab bc ca) + 3abc

Then, a³ + b³ + c³ = 3abc

$\frac{a³ + b³ + c³}{abc} = 3$

$\frac{a³ }{abc} + \frac{b³}{abc} + \frac{c³}{abc} = 3$

$\frac{a²}{bc} + \frac{b²}{ca} + \frac{c²}{ab} = 3$

$\huge\fbox\pink{☆Hence\: The\: answer\: is\: 3\:}$