Question

if a+b+c=0, evaluate a²/bc+b²/ca+c²/ab​

Answer 1

Answer:

please mark me as brainliest

Step-by-step explanation:

LCM is ABC

a^2/BC+b^2/ca+c^2/ab=(a^3+b^3+c^3)/ABC

if a+b+c=0 then a^3+b^3+c^3=3abc

3abc/3abc

Answer.3

Answer 2

Answer:

$\frac{a^2}{bc} +\frac{b^2}{ca} +\frac{c^2}{ab} = 3$.

Step-by-step explanation:

Remember this, a³ + b³ + c³ = (a+b+c)(a²+b²+c²-ab-bc-ca) + 3abc.

Given a+b+c = 0.

∴ a³ + b³ + c³ = 3abc.

$\frac{a^2}{bc} +\frac{b^2}{ca} +\frac{c^2}{ab}$

= $\frac{a^3 + b^3 + c^3}{abc}$

= 3abc/abc

= 3.