If a+b+c=0 find the value of (a²\bc+b²\ca+c²\ab)
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a+b+c = 0
then , by formula a³+b³+c³ = 3abc. (equation 1)
a²/bc + b²/ca + c²/ab
=> mailing denominator equal,
=> a²(a)/bc(a) + b²(b)/ca(b) + c²(c)/ab(c)
=> a³/abc + b³/abc + c³/abc
=> a³+b³+c³/abc
from equation 1 ,
=> 3abc/abc => 3
hope this helps
then , by formula a³+b³+c³ = 3abc. (equation 1)
a²/bc + b²/ca + c²/ab
=> mailing denominator equal,
=> a²(a)/bc(a) + b²(b)/ca(b) + c²(c)/ab(c)
=> a³/abc + b³/abc + c³/abc
=> a³+b³+c³/abc
from equation 1 ,
=> 3abc/abc => 3
hope this helps
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