Question

If a+b+c=0, find the value of x/y^(a²+b²)×y/x^(c²)×[(y/x]^–1)]^2ab×y/x^(a+b/c)×y/x

Plzzzz help!

Answer 1

1 is the correct answer

Answer 2

Ans is 1

first simplify all in only x\y form and add all the powers...

$= \frac{x {}^{(a {}^{2} + b {}^{2} + 2ab - c {}^{2} - ( \frac{a + b + c}{c} ) } }{y {}^{(a {}^{2} + b {}^{2} + 2ab - c {}^{2} - ( \frac{a + b + c}{c} ) } } \\ = \frac{x {}^{(a + b) {}^{2} - c {}^{2} } }{y {}^{(a + b) {}^{2} - c {}^{2} } } \\ = \frac{x {}^{(a + b + c)(a + b - c)} }{y {}^{(a + b + c)(a + b - c)} } \\ = \frac{x {}^{0} }{y {}^{0} } \\ = 1$