Question

if a+ b+c =0 please answer in brief ​

Answer 1

Answer:

a2/bc+b2/ca+c2/ab=3

Step-by-step explanation:

a2/bc+b2/ca+c2/ab=3

Multiplying by abc both side

==> a3+b3+c3=3abc

==>(a+b)3-3ab(a+b) +c3=3abc

As we know that a+b+c =0

==>a+b = -c

==> (-c) 3 -3ab(-c) +(c)3=3abc

==> 3abc=3abc

L. H. S= R. H. S

Proved

Hope its helpful

Answer 2

Step-by-step explanation:

if a+b+c=0

then,a+b=-c

now,a^2/bc+b^/ca+c^2/ab=3

or,a^3+b^3+c^3/abc=3

or,a^3+b^3+c^3=3abc

or,a^3+b^3-3abc=-c^3

or,a^3+b^3-{-3ab(a+b)}=-c^3

or,a^3+b^3+3ab(a+b)=-c^3

or,(a+b)^3=-c^3

or,-c^3=-c^3

so,L.H.S=R.H.S[PROVED]

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