Question

If a+b+c=0
proove that
a^3+b^3+c^3=3abc

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Answer 1

Answer:

Given

a+b+c=0

as we know that,

a^3+b^3+c^3-3abc=(a+b+c)(a^+b^2+c^2-ab-bc-ac)

a^3+b^3+c^3-3abc=0

a^3+b^3+c^3=3abc

hope it helps