Question

if a+b+c=0 prove a3+b3+c3=3abc​

Answer 1

hope it will help you further problems follow me

Answer 2

Step-by-step explanation:

$a + b + c = 0 \\ a + b = - c \\ (a + b) {}^{3} = {( - c)}^{3} \\ {a}^{3} + {b}^{3} + 3 {a}^{} b(a + b) = - {c}^{3} \\ {a}^{3} + {b}^{3} + 3 {a}^{} b( - c) = - {c}^{2} \\ {a}^{3} + {b}^{3} + {c}^{3} = 3abc$

hence proved