Question

if a+b+c=0,prove that :- a^2/bc+b^2/ab+c^2/ca=3​

Answer 1

Answer:

a^2/bc +b^2/ac+c^2/ab

Now ,multiply the numerator and denomerator of a^2/bc by a

Similarly the second and third one by '’b “and “c” respectively

So now we get ..

a^3/abc+b^3 /abc+c^3/ abc

= a^3+b^3+c^3/ abc

= ((a+b+c)(a^2+b^2+c^2-ab-bc-ca))+3abc / abc. [ From the formula]

Now you can obviously see the result

=3abc/abc [a+b+c=0]