Math, asked by nandini1541, 9 months ago

if a+b+c=0,prove that :- a^2/bc+b^2/ab+c^2/ca=3​

Answers

Answered by BrotishPal
1

Answer:

a³+b³+c³ -3abc = (a+b+c)(a²+b²+c²-ab-bc-ca)

as a+b+c =0

so, a³+b³+c³=3abc....... u can do the rest I guess

Similar questions