if a+b+c=0,prove that :- a^2/bc+b^2/ab+c^2/ca=3
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a³+b³+c³ -3abc = (a+b+c)(a²+b²+c²-ab-bc-ca)
as a+b+c =0
so, a³+b³+c³=3abc....... u can do the rest I guess
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