If a+b+c=0, prove that a^2/bc+b^2/ca+c^2/ab=3
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Lcm of denominator will be abc
therefore a^3 + b^3 + C^3/abc = 3
according to identity of a+b+c = 0 then
a^3 + b^3 + c^3 = 3abc
3abc/abc = 3
therefore a^3 + b^3 + C^3/abc = 3
according to identity of a+b+c = 0 then
a^3 + b^3 + c^3 = 3abc
3abc/abc = 3
diyabhardwaj021:
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