If a+b+c =0 prove that : a^2bc+b^2ab+c^2ca=3
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Answered by
2
Answer:
Given,
(a+b+c) = 0
(a+b+c)^3 = 0
» a^3 +b^3 +c^3 -3abc = 0
» a^3 +b^3 +c^3 = 3abc
divide throughout by abc.
» a^2bc+b^2ac +c^2ab=3
Answered by
1
Answer:
no.
Step-by-step explanation:
no.........................no
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