Question

If a+b+c=0,prove that a^3+b^3+ 8c^3 -6abc=0​

Answer 1

Step-by-step explanation:

I hope this is your answer

Answer 2

Answer:

$since \: {a}^{3} + {b}^{3} \: + {c}^{3} - 3abc = (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - bc - ca - ab) \\ given \: a + b + c = 0 \\ {a}^{3} + {b}^{ 3} + {c }^{3} - 3abc = 0 \\ {a }^{3} + {b}^{3} + {c}^{3} = 3abc$

Step-by-step explanation:

$\huge\frak\purple{@PreciousLily}</p><p>$