if a+b+c=0 ,prove that a2/ab+b2/bc+c2+ca=3
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a^2/ab+b^2/bc+c^2/ca=3
(a^3 + b^3 +c^3) / (abc) =3 -------(i)
as we know that, when a+ b + c =0 then,
a^3 + b^3 +c^3 = 3abc
substitute the value for a^3 + b^3 + c^3 in (i)
3abc / abc =3
3 = 3
thus, proved.☺
(a^3 + b^3 +c^3) / (abc) =3 -------(i)
as we know that, when a+ b + c =0 then,
a^3 + b^3 +c^3 = 3abc
substitute the value for a^3 + b^3 + c^3 in (i)
3abc / abc =3
3 = 3
thus, proved.☺
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