Question

if a+b+c=0,prove that :a2/bc+b2/ab+c2/ca=3​

Answer 1

Answer:

a³+b³+c³ - 3abc = (a+b+c)(a²+b²+c²-ab-bc-ca)

since a+b+c = 0

then

a³+b³+c³ - 3abc = 0 x (a²+b²+c²-ab-bc-ca)

a³+b³+c³ - 3abc = 0

a³+b³+c³ = 3abc