if a+b+c=0 prove that a3+b3+c3=3abc
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Answered by
71
dear friend
i have provided the answer in the attachment below
pls do mark my answer as brainliest
by mistake i have given as x , y , z
pls substitute as a , b, c
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Answered by
66
Step-by-step explanation
Identity:
a^3 + b^3 + c^3 - 3abc = (a+b+c)(a^2 +b^2 +c^2 - 2ab -2bc- 2ca)
if a+b+c=0, = 0 *(a^2 +b^2 + c^2 -2ab-2bc-2ca)
a^3 +b^3 +c^3 -3abc = 0
a^3+b^3+c^3 = 3abc
Proved!
pls mark as brainliest..
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