Math, asked by kilarimadhavi11, 1 year ago

if a+b+c=0 prove that a3+b3+c3=3abc

Answers

Answered by deeku004
71

dear friend

i have provided the answer in the attachment below

pls do mark my answer as brainliest

by mistake i have given as x , y , z

pls substitute as a , b, c

Attachments:
Answered by dhivyaarai
66

Step-by-step explanation

Identity:

a^3 + b^3 + c^3 - 3abc = (a+b+c)(a^2 +b^2 +c^2 - 2ab -2bc- 2ca)

if a+b+c=0,                    = 0 *(a^2 +b^2 + c^2 -2ab-2bc-2ca)

a^3 +b^3 +c^3 -3abc    = 0

a^3+b^3+c^3                 = 3abc

Proved!

pls mark as brainliest..

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