If a+b+c=0 prove that b^2-4ac is a square
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b^2-4ac
=(-a-c)^2-4ac (b=-a-c)
=a^2+c^2+2ac-4ac
=a^2+c^2-2ac
=(a-c)^2
Hence, 'tis proved that the given expression is a square.
=(-a-c)^2-4ac (b=-a-c)
=a^2+c^2+2ac-4ac
=a^2+c^2-2ac
=(a-c)^2
Hence, 'tis proved that the given expression is a square.
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