if a+b+c=0,show that: a^3+b^3+c^3=3abc.
Answers
Answered by
1
Step-by-step explanation:
as there are 3 used in the calculation so that is why 3 is common and also a +b+c is there that is why the answer is 3abc
Answered by
1
Answer:
a+b+c=0
a+b=-c
(a+b)³=(-c) ³
a³+b³+3ab(a+b)=(-c) ³
from 2nd line
a³+b³+3ab(-c) =(-c) ³
a³+b³-3abc=-c³
a³+b³+c³=3abc proved
Similar questions