if a+ b + c = 0 show that a3 + b3+ c3 = 3abc .
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We know that
a³ + b³ + c³ - 3abc = ( a + b + c ) ( a² + b³ + c³ - ab - bc - ca )
Putting
a + b + c = 0 on R.H.S ., We get
a³ + b³ + c³ - 3abc = 0
a³ + b³ + c³ = 3abc .
a³ + b³ + c³ - 3abc = ( a + b + c ) ( a² + b³ + c³ - ab - bc - ca )
Putting
a + b + c = 0 on R.H.S ., We get
a³ + b³ + c³ - 3abc = 0
a³ + b³ + c³ = 3abc .
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