If a+b+c = 0, show that a³+b³+c³ = 3abc
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Answered by
2
Step-by-step explanation:
(a+b+c)³ it is the formula.then a+b+c=0 so
0³ =0 proved
Answered by
2
- Given, a+b+c = 0 ............. (Equation 1)
- On solving above equation :
- a+b = -c ............(Equation 2)
- On cubing both sides of Equation 2 :
- (a+b) ³ = (-c) ³
- a³ + b³ + 3ab(a+b) = -c³
- We know that a+b = -c (from equation 2)
- a³ + b³ + 3ab(-c) = -c³
- a³ + b³ - 3abc = -c³
- a³ + b³ + c³ = 3abc
Hence proved...!!!
Hope it helps... ❤
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