Math, asked by Aditya20138S, 9 hours ago

If a+b+c = 0, show that a³+b³+c³ = 3abc​

Answers

Answered by kaziekramulhuda1647
2

Step-by-step explanation:

(a+b+c)³ it is the formula.then a+b+c=0 so

0³ =0 proved

Answered by UniquePrincess1234
2
  • Given, a+b+c = 0 ............. (Equation 1)
  • On solving above equation :
  • a+b = -c ............(Equation 2)
  • On cubing both sides of Equation 2 :
  • (a+b) ³ = (-c) ³
  • a³ + b³ + 3ab(a+b) = -c³
  • We know that a+b = -c (from equation 2)
  • a³ + b³ + 3ab(-c) = -c³
  • a³ + b³ - 3abc = -c³
  • a³ + b³ + c³ = 3abc

Hence proved...!!!

Hope it helps...

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