Question

If a + b + c = 0, the straight line 2ax + 3by + 4c = 0 passes through the fixed point (a, b) then
a +38=
(A) 2
(B)
4
(C) 6
(D) -2​

Answer 1

We have,

a+b+c=0......(1)

2ax+3by+4c=0......(2)

Now,

On multiplying by 4 in equation (1) and we get,

4a+4b+4c=0......(3)

From equation (2) and (3) to and we get,

x=2,y=

3

4

Hence, this is the answer.

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