Question

if a + b + c=0 then 1/( a + b)( b + c) + 1 /( b + c)( c+a)+1/(c+a)(a+b) equal to​

Answer 1

Answer:

is equal to 0

i think it is correct answer

Answer 2

Answer:

0

Step-by-step explanation:

a + b + c = 0  So

a +b = -c

b + c= -a

c + a= -b       Then

$\frac{1}{(a+b)(b+c)} +\frac{1}{(b+c)(c+a)} +\frac{1}{(c+a)(a+b)} \\\\=\frac{1}{(-c)(-a)} +\frac{1}{(-a)(-b)} +\frac{1}{(-b)(-c)}\\ \\Taking L.C.M\\\\=\frac{b+c+a}{abc} =0$