Math, asked by daraz647, 5 months ago

If a+b+c=0, then 2a2b−1c−1⋅2b2c−1a−1⋅2c2a−1b−1 is

Answers

Answered by harshini168512

1

Answer:

0

Step-by-step explanation:

2a2b−1c−1⋅2b2c−1a−1⋅2c2a−1b−1 is 0

Answered by Anonymous

1

Answer:

2a2b−1c−1⋅2b2c−1a−1⋅2c2a−1b−1 is

Step-by-step explanation:

the answer is 0

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