Math, asked by sujithguntha, 6 months ago

if a+b+c=0 then a^2+b^2+c^2/a^2-bc​

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Answered by snowyseret
0

Answer:

if a+b+c=0 and a^2+b^2+c^2=k(a^2-bc) then value of k is (a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca=0 a^2+b ^2+c^2=2(-

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