Question

if a+b+c=0,then a^2+b^2+c^2 is

Answer 1

in the expression we have to squaring both side
(a+b+c)²=0²
a²+b²+c² +2ab+2bc+2ca=0
hence a²+b²+c²=-(2ab+2bc+2ca)

Answer 2

$Answer :\\ \\ Now, \\ \\ {a}^{2} + {b}^{2} + {c}^{2} \\ \\ = {(a + b + c)}^{2} - 2(ab + bc + ca) \\ \\ = {0}^{2} - 2(ab + bc + ca), \\ since \: \: a + b + c = 0 \\ \\ = - 2(ab + bc + ca)$

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