if a+b+c =0 then, a^2/bc+b^2/ca+c^2/ab=
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Answered by
0
Answer:
a³c²+a²b³+b²c³/abc
Step-by-step explanation:
a2/bc+b2/ca+c²/ab
=a³c²+a²b³+b²c³/abc
Answered by
1
Step-by-step explanation:
(a+b+c)3=a3+b3+c3+3(a+b+c)(ab+bc+ca)−3abc
0=a3+b3+c3+0−3abc
a3+b3+c3=3abc
a3+b3+c3abc=3
a2bc+b2ac+c2ab=3
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