Question

if a+b+c=0 then a^3 +b^2 +c^3 /6abc is​

Answer 1

Answer:

a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - ac - bc).

⇒ a^3+b^3+c^3-3abc=0

⇒a^3+b^3+c^3=3abc

a^3 +b^2 +c^3 /6abc=3abc/6abc=1/2

a^3 +b^2 +c^3 /6abc=1/2