If a+b+c=0 then a^3+b^3+c^3=
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Answered by
5
Answer:
Step-by-step explanation:
a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ac)
a+b+c=0
a^2+b^2+c^2-3abc=0
a^2+b^2+c^2=3abc
Answered by
1
Answer:
Step-by-step explanation:
Step-by-step explanation:
a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ac)
a+b+c=0
a^2+b^2+c^2-3abc=0
a^2+b^2+c^2=3abc
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