If a+b+c=0, then (a^3+b^3+c^3) ^2=
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Answer:
Since, a
3
+b
3
+c
3
−3abc=(a+b+c)(a
2
+b
2
+c
2
−bc−ca−ab)
Given, a+b+c=0
∴a
3
+b
3
+c
3
−3abc=0
∴a
3
+b
3
+c
3
=3abc
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