Math, asked by Anonymous, 6 months ago

If a+b+c=0, then (a^3+b^3+c^3) ^2=

Answers

Answered by abhishekshuklaalps
0

Answer:

Since, a

3

+b

3

+c

3

−3abc=(a+b+c)(a

2

+b

2

+c

2

−bc−ca−ab)

Given, a+b+c=0

∴a

3

+b

3

+c

3

−3abc=0

∴a

3

+b

3

+c

3

=3abc

Similar questions