Question

if a+b+c=0 then a^3+b^3+c^3-3abc =​

Answer 1

If a+b+c=0 then a^3+b^3+c^3-3abc = 0

Since ,

a^3+b^3+c^3-3abc= 0 (a2.....)

= 0

Therefore; - a^3 + b^3 + c^3 = 3abc

Answer 2

Answer:

Zero

Step-by-step explanation:

Since, a^3 + b^3 +c^3 - 3abc = (a+b+c)(a^2+b^2+c^2 -ab -bc -ac)

And it is given that a+b+c=0