If a+b+c=0,then a^3+b^3+c^3=3abc
solve the equation explain
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A+b+c=0
A+b=-c
Cubing both sides
A^3+b^3+3Ab(a+b)=-c^3
a^3+b^3+3ab*-c=-c^3
a^3+b^3-3abc=-c^3
therefore
a^3+b^3+c^3=3abc
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A+b=-c
Cubing both sides
A^3+b^3+3Ab(a+b)=-c^3
a^3+b^3+3ab*-c=-c^3
a^3+b^3-3abc=-c^3
therefore
a^3+b^3+c^3=3abc
plz mark me as brainlist
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