Question

if a+b+c=0 then a^3 +b^3+c^3 is equal to ​

Answer 1

Answer:

3abc

Now, a3+b3 + c3 = (a+ b + c) (a2 + b2 + c2 – ab – be – ca) + 3abc

[using identity, a3+b3 + c3 – 3 abc = (a + b + c)(a2+b2+c2 –ab–bc-ca)] = 0 + 3abc [∴ a + b + c = 0]

a3+b3 + c3 = 3abc.

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Answer 2

Answer:

Step-by-step explanation:

A+B+C=0

THEN( A+B+C)^2

=A^2+ B^2 +C^2 +2(AB +BC+ CA)

EXTRACT A+B+C FROM ONE VARIABLE

(A+B+C)^2+2(AB +BC+ CA)

(0)^2+2((AB +BC+ CA)

IF A+B+C =0 THEN NO NEED TO FIND AB +BC+CA

SO ANSWER = 0

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