If a+b+c=0 then a'+ b³ + c³ =
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Answer:
3abc
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Since...
a³+b³+c³ −3abc=(a+b+c)(a²+b²+c²−bc−ca−ab)
Given that...
a+b+c=0
∴a³+b³+c³−3abc=0
∴a³+b³+c³ =3abc
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