If a+b+c= 0 then a cube + b cube + c cube =3abc
Answers
Answered by
77
HEYA...!!
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a+b+c = 0 (given)
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a³ + b³ + c³ = 3abc
a³ + b³ + c³ - 3abc = 0
(a+b+c) (a²+b²+c²-ab-bc-ca) = 0
0 x (a²+b²+c²-ab-bc-ca) = 0
0 = 0
LHS = RHS
___________________
HOPE IT WILL HELP U... MARK MY ANSWER AS BRAINLIEST IF U FIND MY ANSWER HELPFUL
.........................................................
a+b+c = 0 (given)
__________________
a³ + b³ + c³ = 3abc
a³ + b³ + c³ - 3abc = 0
(a+b+c) (a²+b²+c²-ab-bc-ca) = 0
0 x (a²+b²+c²-ab-bc-ca) = 0
0 = 0
LHS = RHS
___________________
HOPE IT WILL HELP U... MARK MY ANSWER AS BRAINLIEST IF U FIND MY ANSWER HELPFUL
Answered by
7
Answer:
3ABC
Step-by-step explanation:
a cube+b cube + c cube = 3 abc
a cube+b cube + c cube - 3 abc = 0
(a+b+c) (a square + b square c square -ab-bc-ca) =0
0×(a square+ b square+ c square - ab- bc - ca)=0
LHS=RHS
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