Math, asked by Anas111111111111, 1 year ago

If a+b+c= 0 then a cube + b cube + c cube =3abc

Answers

Answered by Priyu19
77
HEYA...!!
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a+b+c = 0 (given)
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a³ + b³ + c³ = 3abc
a³ + b³ + c³ - 3abc = 0
(a+b+c) (a²+b²+c²-ab-bc-ca) = 0
0 x (a²+b²+c²-ab-bc-ca) = 0
0 = 0
LHS = RHS
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Answered by suryaprakhash2215
7

Answer:

3ABC

Step-by-step explanation:

a cube+b cube + c cube = 3 abc

a cube+b cube + c cube - 3 abc = 0

(a+b+c) (a square + b square c square -ab-bc-ca) =0

0×(a square+ b square+ c square - ab- bc - ca)=0

LHS=RHS

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