if a+b+c=0 then, a cube + b cube + c cube
atharva13:
dude what is question
is it to proove a^3+b^3+c^3=3abc
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Answered by
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a+b+c=0-----(1)
a³+b³+c³=(a+b+c)(a²+b²+c²-ab-bc-ca)+3abc
= 0*(a²+b²+c²-ab-bc-ca)+3abc
[we used (1) above]
=3abc
a³+b³+c³=(a+b+c)(a²+b²+c²-ab-bc-ca)+3abc
= 0*(a²+b²+c²-ab-bc-ca)+3abc
[we used (1) above]
=3abc
Answered by
0
Answer:
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Step-by-step explanation:
a^3 +b^3 +c^3 — 3abc = (a+b+c)(a^2+b^2+c^2– ab- bc — ca)
If a+b+c=0 then
a^3+b^3+c^3= 3abc
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