Question

if a+b+c=0 then a
${a}^{3} + {b}^{3 + {c}^{3} =$
?.?​

Answer 1

Answer:

a³ + b³+c³ = (a+b+c)(a²+b²+c²-ab-bc-ca) +3abc

=> put value of a+b+c = 0

=> a³+b³+c³ = 0 + 3abc

=>a³+b³+c³ = 3abc

Answer 2

Step-by-step explanation:

a+b = - c

now cube it

${(a + b)}^{3} = - {c}^{3}$

${a}^{3} + {b}^{3} + 3ab(a + b) = - {c}^{3}$

${a}^{3} + {b}^{3} + {c}^{3} = - 3ab( - c)$

which is equal to. 3abc

hope this will help u