If a + b + c = 0, then a²/bc + b²/ca + c²/ab=?
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Step-by-step explanation:
Given,
a+b+c=0
we know that,
if a+b+c=0, then a³+b³+c³=3abc
Now,
(a²/bc)+(b²/ac)+(c²/ab)=(a³+b³+c³)/abc
= 3abc/abc
=3
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Step-by-step explanation:
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