Math, asked by rakjayp, 6 hours ago

if a+b+c=0 then [a2/bc+b2/ca+c2/ab] =?​

Answers

Answered by saurabhchaure007
1

Answer:

Using the formula, a^3 + b^3 + c^3 = (a + b + c) (a^2 + b^2 + c^2 ab bc ca) + 3abc

If a+b+c=0,

then a^3 + b^3 + c^3 = 3abc

abc

a

3

+b

3

+c

3

=3

abc

a

3

+

abc

b

3

+

abc

c

3

=3

bc

a

2

+

ca

b

2

+

ab

c

2

=3

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