Question

if a+b+c=0 then, a³+b+³c³=3abc
for a= -10, b= 6, c= 4.​

Answer 1

$\bold{QuestioN:}$

If a+b+c=0 then, a³+b+³c³=3abc

for a= -10, b= 6, c= 4.​

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a+b+c=0,

a³+b³+c³=3 a b c,

a= -10,

b=6,

c=4,

So, (-10)³+6³+4³=3 a b c,

-1000+280= -720,

-720=-720.

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Answer 2

Answer:

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Step-by-step explanation:

a+b+c=0,

a³+b³+c³=3 a b c,

a= -10,

b=6,

c=4,

So, (-10)³+6³+4³=3 a b c,

-1000+280= -720,

-720=-720.