Math, asked by likithaindu, 10 months ago

if a+b+c=0 then a³+b³+c³=​

Answers

Answered by sravyakrishna73
0

3abc

Step-by-step explanation:

 a^3+b^3+c^3−3abc=(a+b+c)(a^2+b^2+c^2−bc−ca−ab)

Given, a+b+c=0

a^3+b^3+c^3−3abc=0*(a^2+b^2+c^2−bc−ca−ab)

∴a^3+b^3+c^3−3abc=0

a^3+b^3+c^3=3abc

Answered by rg6409238
0

Answer:

If a+b+c=0 then a3+b3+c3 = 3abc

I Hope It's Useful Answer

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