if a+b+c=0 then a³+b³+c³=
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3abc
Step-by-step explanation:
a^3+b^3+c^3−3abc=(a+b+c)(a^2+b^2+c^2−bc−ca−ab)
Given, a+b+c=0
a^3+b^3+c^3−3abc=0*(a^2+b^2+c^2−bc−ca−ab)
∴a^3+b^3+c^3−3abc=0
∴a^3+b^3+c^3=3abc
Answered by
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Answer:
If a+b+c=0 then a3+b3+c3 = 3abc
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